Question

12

Answer 1

(6,9) n (10,13) are closest to line
so they should be used (:

Answer 2

Awesome thanks for helping me out, what's B?

Answer 3

slope will be y2-y1 / x2-x1

Answer 4

thats 13-9/10-6 = 4/4 = 1

Answer 5

so your slope is 1

Answer 6

Perfect, C?

Answer 7

well i think it will be y= mx+b
m= 1
so = x+b
now as for b
m nt sure @ikram002p

Answer 8

point slop
\((y-y_0)=m(x-x_0)\)
so ur slop =1 ?
and point lets say (6,9)
\((y-9)=m(x-6)\)

Answer 9

what you wrote @aajugdar is D

Answer 10

So this is C? (Y-9)=m(x=6)

Answer 11

oh i see

Answer 12

C) (y-9)=m(x=6)
D) ?

Answer 13

?

Answer 14

C) (10-13)^1=m(6-9)= ??

Answer 15

(y−9)=m(x−6)
where m=1

Answer 16

A) (6,9) (10,13) circled above
B) Y2-y1/x^2-x^1= 13-9/10-6=4/4=1. Slope=1
C) -3= 4m+b
D) 1

Answer 17

Is this right?

Answer 18

D will be y=x+3

Answer 19

A) (6,9) (10,13) circled above
B) Y2-y1/x^2-x^1= 13-9/10-6=4/4=1. Slope=1
C) -3= 4m+b
D) -3=4m+3

Answer 20

o_o
@ikram002p help him
idk how to find regression equation

Answer 21

But are A-C correct?

Answer 22

CD are not correct

Answer 23

Help then somebody please

Answer 24

C) 4 = 4 + 1

Answer 25

you dont put values of x and y in it ,just x0 and y0

Answer 26

y4 = x4 + 1

Answer 27

c ~ (y−9)=1(x−6)
d~ y=x+3

Answer 28

E !~ she will tell
i dnt knw hw to do it

Answer 29

Okay thanks!

Answer 30

so time to learn the least squares regression line ?

Answer 31

u have these values