write the slope-intercept forms of the equations of the lines through the given point (a) parallel to the given line and (b) perpendicular to the given line.
Point (3,-2) and the line is 5x-4y= 8

Question

write the slope-intercept forms of the equations of the lines through the given point (a) parallel to the given line and (b) perpendicular to the given line. 
Point (3,-2)  and the line is 5x-4y= 8

jack1 · Answer

Point (3,-2)  and the line is 5x-4y= 8
slope-intercept form
y = mx +c
so
5x-4y= 8
5x- 8= 4y
y = (5/4) x - 2  ==> slope intercept form of original line

jack1 · Answer

a) parallel to this line
  y = (5/4) x + c   and passes through 3,-2
-2 = (5/4) 3 + c 
-2 = 15/4 + c 
  c =  -2   -   15/4    = -2   -3.75    = -5.75

so equation of the parallel line is 
  y = (5/4) x - 5.75

goformit100 · Answer

@Jack1 is correct

jack1 · Answer

@goformit100 ... dude, you've blocked me... i cant pm u... why?