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you have to prove they are similar
How do I do that?
well you have congruent triangles over a straight line you can prove the opposite angle being equal and lines in ratio
@CaseyCarns angle ACB = angle GCE...and angle BAC = angle CGE..so by AA similarity
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@rishavraj is that my entire answer?
makes sense they are congruent so AB is parallel to DG alternate angles are equal good one @rishavraj
yes
two angles are equal ultlimately 3rd angle will be equal so they are similar
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