Question

A few simple trig questions:
1. evaluate csc 5pi/4
a. sqrt 2
b. sqrt2/2
c. -sqrt2
d. -sqrt2/2

2. What is tan 2pi/3

a. sqrt 3
b. -sqrt3/3
c. 1
d. -sqrt3

Answer 1

I don't understand exactly how to do these problems..

Answer 2

\[csc =\dfrac{1}{sin}\]
so that you just find the value of sin (5pi/4) then plug back

Answer 3

sin (5pi/4) =??

Answer 4

can you show me how I find sin 5pi/4 ?

Answer 5

do I use my calculator?

Answer 6

do you know sin (pi/4) =?

Answer 7

nooo I barly know anything about anything that's why I need help

Answer 8

wait where did sin pi/4 come in ?

Answer 9

so!!! you have a trouble. hihihi... google to tell me what is sin(pi/4)

Answer 10

I guide you step by step how to find sin (5pi/4) from sin (pi/4) hihihihi

Answer 11

google says it = 0

Answer 12

hahahaha.... wut??? send me the link. .......

Answer 13

does google mean 1?

Answer 14

https://www.google.com/#q=sin+pi/4

Answer 15

https://www.google.com/search?q=unit+circle+chart&tbm=isch&imgil=Wd0Fq1Ak9Wv4OM%253A%253Bhttps%253A%252F%252Fencrypted-tbn1.gstatic.com%252Fimages%253Fq%253Dtbn%253AANd9GcQDDR5mey_0Rv1aMf3ZkvGp7sNddQnDvA6ewjXFYTsih15Yi8hAew%253B1407%253B555%253B72kSWtuUj6KoBM%253Bhttp%25253A%25252F%25252Fperfect4panic.wordpress.com%25252F2012%25252F04%25252F18%25252Funit-circle-and-trigonometric-identity-reference-page%25252F&source=iu&usg=__DGWsuclIgFIM3qw9UapPeIaYNWs%3D&sa=X&ei=q1-bU_SNA4PfsASI-ICgDg&ved=0CCcQ9QEwBA&biw=1600&bih=769#facrc=_&imgdii=_&imgrc=Wd0Fq1Ak9Wv4OM%253A%3B72kSWtuUj6KoBM%3Bhttp%253A%252F%252Fkarlcgeorge.files.wordpress.com%252F2007%252F12%252Ftrig2.jpg%3Bhttp%253A%252F%252Fperfect4panic.wordpress.com%252F2012%252F04%252F18%252Funit-circle-and-trigonometric-identity-reference-page%252F%3B1407%3B555

Answer 16

you put (sin (pi))/4 so, it is = 0. Our angle is sin (pi/4)

Answer 17

is there a way to know what it is without google? cause in school I wanna know how to find it

Answer 18

and you have sin (5pi/4) there, right? it says sin (5pi/4) = \(\dfrac{-\sqrt2}{2}\)

Answer 19

Yes, there is another way MEMORIZE some SPECIAL trig values. That's the way ALL math students do

Answer 20

me too.

Answer 21

but it's not hard if you have method.

Answer 22

it means \(cos (\pi/6)=\dfrac{\sqrt{3}}{2}~~ and~~ sin(\pi/6)= \dfrac{1}{2}\)