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Solve 4x = 12 x ≈ 0.27 x ≈ 0.56 x ≈ 1.79 x ≈ 19.93
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thats 4x or 4x^2
:)
4x = 12 x = 3...is the problem written correctly ?
it is 4^x = 12 lol
i think its x^2 which would make root 3 = 1.72
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oh
take log hehe
so it will be x log(4) = log(12) x= log(12)/log(4) so calculate now
log 12 = 1.07 log 4= 0.60
so x = 1.783333333333
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so its c o_o
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