Sketch graph of following curve, indicating points of intersection of curve with axes
y=x(x+1)(x-2)
@Hero
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OpenStudy (eric_d):
Sketch graph of following curve, indicating points of intersection of curve with axes
hero (hero):
Sketching the graph of a function is usually a very involved process, but let's just take it one step at a time. First, we will find the x and y intercepts. @eric_d, Do you know how to find the x-intercepts of the given equation?
OpenStudy (eric_d):
x-inter= .. when y=0
hero (hero):
So when y = 0, we'll have
0 = x(x + 1)(x - 2) right? Now what can we do from here to finish finding the x-intercepts?
OpenStudy (eric_d):
yes, so, x=0,-1 and 2
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OpenStudy (eric_d):
?
hero (hero):
Very good. So on your xy plane, you'll need to plot the points (0,0), (-1,0) and (2,0) correct?
OpenStudy (eric_d):
yes, I gt it
Thanks @Hero
hero (hero):
Next find the y-intercept. Any idea how to find that?
OpenStudy (eric_d):
y-inter=0
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