Question

prove the following:

1. (1-sinxtanx)/1+secx=cosx

2. (1+sinx)/cosx =cosx/1-sinx

Answer 1

\(\Huge \frac {(1-\sin x\tan x)}{1+\sec x}=\cos x \)

Answer 2

LHS IS NOT EQUAL TO RHS

Answer 3

The two sides are not equal

Answer 4

ur correct No.name

Answer 5

In the second problem
Multiply both the num and denom by
(1-sinx)

In the numerator it would become cos^2 x as

(1+sinx)(1-sinx) = cos^2 x

Which you can write as cos x cos x


On the RHS multiply by the numerator by cos x and cos x

You would get cos x cos x /cos x (1 - sin x )

Which is the same as LHS hence proved