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Help! should I use the law of cos than find the area? find the area of the triangle with the sides of 3,9, and 10
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Use Heron's formula: If you have a triangle with sides, a, b, c, then: \(A = \sqrt{s(s - a)(s - b)(s - c)}\) \(s = \dfrac{a + b + c}{2}\)
Is there another way to do this?
There's always more than one way to do any mathematics.
Well, what is another way to do this? @Hero
|dw:1402860403867:dw| Find the height of \(d\), then you'd be able to use \(A_{\triangle} = \frac{bh}{2}\)
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