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What is the value of x?
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inscribed angle theorem: angle of inscribed angle is half the central angle or arc
|dw:1402861652266:dw|
So according to that theorem, we have \(\dfrac{1}{2}(6x-8) = 10x+10\)
is this correct?
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on LHS of first line, it supposed to be 1/2, not 2
ltp1212 has the correct steps and answer
you can either do 2*(6x-8) = 10x + 10 or (1/2)*(10x+10) = 6x - 8
@geerky42 no
2*(angle GFE) = (arc GE) or (1/2)*(arc GE) = (angle GFE)
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when i do 1/2(6x-8)=10x+10 i get x=-2
oh that's me then. sorry.
@jim_thompson5910 thank you
np and no worries
@geerky42 thanks anyways
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