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Help Please n_n - what is the value of p? x=1/4 y^2
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its a parabola \[x=\frac{ 1 }{ 4 } y^2\]
well the standard form is \[4p(x - h) = (y - k)^2\] it appears the vertex is at the origin so you have \[4px = y^2\] so I'd multiply both sides of your equation by 4 so you can compare it to the standard form and then find p
ok so i got 4x=y^2 anddd if i compare this to the above one p=1 ??? @campbell_st
that's what my answer would be
ohhhhh okkkk thank you
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