Question

Explain, in complete sentences, how you would factor 400x8 - 36.

Answer 1

\[4\left[ \left( 10 x^4 \right)^2-3^2 \right]=4\left( 10 x^4+3 \right)\left( 10x^4-3 \right)\]
\[=4\left[ \left( 10x^4 \right)+3 \right]\left[ \left( \sqrt{10} x^2\right)^2-\left( \sqrt{3} \right)^2 \right]\]
=?

Answer 2

is that x to the 8th ?

Answer 3

find factors of each term
400x^8 = (2*10*x^4)^2 and 36 = 6^2
difference of 2 squares
a^2 -b^2 = (a + b)(a - b)
a = 20x^4 and b = 6