Question

Simplify 8/2+2i

Answer 1

We'll multiply the top and bottom by the `conjugate` of our denominator,
\[\Large\rm \frac{8}{2+2\mathcal i}\color{royalblue}{\left(\frac{2-2\mathcal i}{2-2\mathcal i}\right)}\]

Answer 2

Do you recall what happens when we multiply conjugates (the orange part) ? :)\[\Large\rm =\frac{8(2-2\mathcal i)}{\color{orangered}{(2+2\mathcal i)(2-2\mathcal i)}}\]

Answer 3

\(\large \bf {\color{orangered}{ (a-b)(a+b) }}= a^2-b^2\)