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OpenStudy (anonymous):
what horizontal force will accelerate a 400kg crate at 1 m/s/s across a factory floor against a friction force half its weight
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OpenStudy (anonymous):
Taking 'g' to be 10ms^-2, therefore weight = 400*10= 4000N Frictional force= 2000N Using netwon 2nd law 'R.F= ma', we have: X-2000= 400*1 X= 400+2000= 2400N
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