Question

Using (f circle g)(x).
a) f(x) = x + 5
g(x) = x - 8

b) f(x) = 2x - 3
g(x) = x + 4

c) f(x) = 3x - 1
g(x) = 9x^2 - 1

d) f(x) = 2x^2 - x -1
g(x) = 4x^2 -1

e) f(x) = x^3 - 1
g(x) = x^2 - 1

Answer 1

use the definition :

\(\large (f\circ g)(x) = f\left(g(x)\right)\)

Answer 2

a) \(f(x) = x + 5\)
\(\color{red}{g(x) = x - 8}\)

\(\large (f\circ g)(x) = f\left(\color{Red}{g(x)}\right)\)
\(\large ~~~~~~~~~~~~~ = f\left(\color{red}{x-8}\right)\)
\(\large ~~~~~~~~~~~~~ = ?\)

Answer 3

just replace `x` by `x-8` in f(x)

Answer 4

ok thank you! :D

Answer 5

what did u get after that step ?