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Trigonometry
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A triangle has a base 2x+1 and height of 6x-3. What value of x would give an area of 240m^2.?
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Solve the following for x:\[\frac{1}{2} (2 x+1) (6 x-3)=240 \]\[x=\frac{\sqrt{161}}{2} \]\[\text{or 6.34429 } \]
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