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8^2-4^2 over 8
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The sum of three consecutive numbers is eight more than twice the lowest number. What are the three numbers?
\[\frac{ 8^{2}-4^{2} }{ 8 }\] is this the problem?
yes
wait nooo
62
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its 37(3-(-2) over 53
Evaluate and simplify if possible
can you answer mine please
\[\frac{ 37(3-(-2) }{ 53 }\] is that it?
yes
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ok so simplify inside the parenthesis (3--2) is the same thing as 3+2. Next multiply 37*5 for the numerator which equals 185 Then divide 53 by 185 so that it equals 3.5
A. 3, 4, 5 B. –11, –12, –13 C. 11, 12, 13 D. 5, 6, 7
its mutiply chocie
yeah
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