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Find the period of the function y=-4 sin t/3
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6pi
thanks! how did you get it?
The following general rules apply to the sine and cosine functions: If y=a sin bx, then the amplitude of the function is |a| (the absolute value of coefficient ' a '), and the period is \[\frac{ 2\pi }{ b }\]
Look carefully at the given y=-4 sin t/3. What is ' a '? What is ' b '? Take your ' b ' value and substitute it into 2pi/b to determine the period.
Hint: ' a '=-4. ' b ' = ?
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I get 2pi/t/3 right?
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