Question

Find the period of the function:
y=1.5 sin (pi/2) x

Answer 1

is it sin(pi x/2), because what you wrote has no period

Answer 2

period of a function
\[y=asin(bx)\] is \[\large\frac{ 2\pi }{ b}\]

Answer 3

ur function is\[y=1.5\sin[(\frac{ \pi }{ 2 })x]\]
just compare with the above equation