Question

The diagonals of a parallelogram have lengths 8 and 14 and they meet at a 60 degree angle. Find the area and the perimeter of the parallelogram.

Answer 1

Use the Law of sines to find the area of one small triangle inside and multiply by 4

Answer 2

\[
\frac{4}{2} 4 ( 7) \sin (60 {}^{\circ})=28 \sqrt{3}
\]

Answer 3

is that the area?

Answer 4

yes