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Factor the polynomial below. 6b^2+3b a. 3b times (2b+1) b. 3b times (2b) c. 3b times (6B+1) d. 3b times (6b^2+3b
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\(\normalsize\color{darkgreen}{ \rm 6b^2+3b }\) factoring out of `3b` \(\normalsize\color{darkgreen}{ \rm 3b(2b)+3b(1) }\) \(\normalsize\color{darkgreen}{ \rm 3b(2b+1) }\)
so its a..
yes
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