Mathematics
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OpenStudy (anonymous):
What is the solution of the system of equations?
{3x+2y+z=7}
{5x+5y+4z=3}
{3x+2y+3z=1}
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rishavraj (rishavraj):
solve it using determinant or elimination method..
OpenStudy (anonymous):
i dont know how to do either. which ways is easiest?
rishavraj (rishavraj):
use elimanation method..subtract 3rd equation from 1st one
OpenStudy (anonymous):
so -3z=6
OpenStudy (anonymous):
z=-2
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rishavraj (rishavraj):
its supposed to be -2z = 6
z = -3
OpenStudy (anonymous):
right. my mistake
rishavraj (rishavraj):
@yelahn are u able to proceed further???
OpenStudy (anonymous):
do i take 2 more equations and substite z for -3 in each then solve for a different variable?
rishavraj (rishavraj):
yeah...
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rishavraj (rishavraj):
@yelahn got the answer???
OpenStudy (anonymous):
almost
rishavraj (rishavraj):
@yelahn k...then whats the answer??? i too got it
OpenStudy (anonymous):
which two equations should i use this time??
rishavraj (rishavraj):
see multiply 1st equation from 5 and 2nd equation from 3..and subtract them.....u will get y
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rishavraj (rishavraj):
@yelahn solved???
OpenStudy (anonymous):
y=-1
rishavraj (rishavraj):
@yelahn yup u r correct...now plug the value of y & z in any equation and get "x"
OpenStudy (anonymous):
x=2.7??
OpenStudy (anonymous):
i made a mistake. let me try again
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rishavraj (rishavraj):
@yelahn for sure try it again...
OpenStudy (anonymous):
x=2
rishavraj (rishavraj):
@yelahn no..u r wrong just plug the value y = -1 and z = -3 in 1st equation..u will get x
OpenStudy (anonymous):
thats what i did
OpenStudy (anonymous):
3x+2(-1)+(-3)=7
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rishavraj (rishavraj):
@yelahn ur eqution is correct....
OpenStudy (anonymous):
now i got x=4.3
rishavraj (rishavraj):
@yelahn 3x-5 = 7
3x = 12
OpenStudy (anonymous):
x=4
rishavraj (rishavraj):
@yelahn this is time u r absolutely correct.....
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rishavraj (rishavraj):
to check ur answer just plug all values in equations and see wether LHS = RHS or not