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What is the additive inverse of the complex number 9 – 4i? A. –9 – 4i B. –9 + 4i C. 9 – 4i D. 9 + 4i
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Additive inverse of a complex number + complex number = 0
Now, can you figure it out ?
I'm guessing it would be between D and A ?
Try adding each of them to 9-4i. Which would result in 0 ?
None of them will result in 0. They either come out to 5, -5 or 13.
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No, see: (A) 9 - 4i - 9 - 4i = -8i (B) -9 + 4i + 9 - 4i = 0 (C) 9 - 4i + 9 - 4i = 18 - 8i (D) 9 + 4i + 9 - 4i = 18 So can you see which option is right ?
Oh okay. I did the math wrong. Thanks :D
No problem :D
Can you help me on one more problem?
Yeah sure
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I will inbox you it.
Ok
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