Question

9-y^2 12y
------*-----
3-y 9+3y

Answer 1

what do we hv to do here?

Answer 2

you're multiplying the two fractions to equal something.

Answer 3

then multiply the numerators and denominators separately and express as a fraction..thats it

Answer 4

\[\frac{ 9-y ^{2} }{ 3-y } * \frac{ 12y }{ 9+3y }\]

Answer 5

Yup!

Answer 6

did you understand ineedromance? he is correct!

Answer 7

\[\frac{ (9-y ^{2})(12y) }{ (3-y)(9+3y) }\]

Answer 8

Thanks guys! I got it :)