solve, assuming a linear equation fits this situation. The value of a graphing calculator is $225. After 2 years, the value of this calculator is $160. Find the value of the calculator after 5 years. (HINT: Let the time now be 0, the time in two years be 2, and time in five years be 5)
@iGreen
(0, 225) (2, 160) Those are your points.
The answer should be in $ o_o
Since, it must be a linear equation. So, it would be of the format: y = ax + b Here, y = value after x years
a = rate at which the value changes b = value at 0 year.
It's not your answer.
Now, it is given that (0,225) and (2, 160) satisfy this equation.
I'm not sure what you want me to do with those points.
I mean x = 0 and y =225 ; x = 2 and y = 160 satisfy the equation.
Now, using these facts solve for a and b.
If I knew how I would.
I can put them in fraction form and cross multiply :D
So the answer is?....
Slope is (160-225)/2 = -32.5 So our equation is: f(x)=-32.5x+225 I can plug this into my graphing calculator and find out what x = 5 is. When x = 5, y = 62.5.
o_o Math is hard. </3
Nah. Is it multiple choice?
Nope. Answer should be in $ though.
Put in 62.50
I made a 40 on that test lololol.
But you got that right.
WAT Which questions did you miss?
Not sure, I moved to the next test. Lol. We'll get it next time.
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