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the graphic of a quadratic function y=f(x) has the maximum at point (3,4). if f(5)=-4, then f(x)=?
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suppose f(x)=ax^2+bx+c a<0 now f(3)=4 f'(3)=0 f(5)=-4 put them and solve the system of equation
i cant understand??
you know derivation ?
if not use this \[f(x)=a(x-b)^2 +c\]
if i substitute x in the equation tere will be 3 unknowns a b and c??
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you know derivation ?
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