Mathematics
8 Online
OpenStudy (anonymous):
Find BC. Round to the nearest tenth.
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OpenStudy (anonymous):
OpenStudy (anonymous):
A.
19.1
B.
20.8
C.
23.1
D.
23.3
OpenStudy (goformit100):
Show your Working.
OpenStudy (anonymous):
@goformit100 what?
OpenStudy (vishweshshrimali5):
He means if you have given a try to the problem then please show your work.
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OpenStudy (goformit100):
Yes that was what I was telling.
OpenStudy (anonymous):
Oh, well i need help on solving this problem i think thats why i posted it
OpenStudy (vishweshshrimali5):
Okay so here is the hint:
Try using sine law of triangles
OpenStudy (vishweshshrimali5):
See, it states that:
\[\large{\cfrac{\sin A}{a} = \cfrac{\sin B}{b} = \cfrac{\sin |dw:1403057514568:dw|C}{c}}\]
OpenStudy (vishweshshrimali5):
That was actually:
\[\large{\cfrac{\sin A}{a} = \cfrac{\sin B}{b} = \cfrac{\sin C}{c}}\]
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OpenStudy (vishweshshrimali5):
A, B and C are angles at respective vertices and a,b,c are sides as represented in the figure.
OpenStudy (anonymous):
I got 20.80
OpenStudy (anonymous):
is that correct?
OpenStudy (vishweshshrimali5):
No try again.
OpenStudy (vishweshshrimali5):
See:
\[\large{\cfrac{\sin C}{c} = \cfrac{\sin B}{b}}\]
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OpenStudy (vishweshshrimali5):
Here, C = 30 deg , c = 11, B = 79 deg, b = ?
OpenStudy (anonymous):
@vishweshshrimali5 alright i got it thank you
OpenStudy (vishweshshrimali5):
np