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Mathematics 8 Online
OpenStudy (anonymous):

Find BC. Round to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (anonymous):

A. 19.1 B. 20.8 C. 23.1 D. 23.3

OpenStudy (goformit100):

Show your Working.

OpenStudy (anonymous):

@goformit100 what?

OpenStudy (vishweshshrimali5):

He means if you have given a try to the problem then please show your work.

OpenStudy (goformit100):

Yes that was what I was telling.

OpenStudy (anonymous):

Oh, well i need help on solving this problem i think thats why i posted it

OpenStudy (vishweshshrimali5):

Okay so here is the hint: Try using sine law of triangles

OpenStudy (vishweshshrimali5):

See, it states that: \[\large{\cfrac{\sin A}{a} = \cfrac{\sin B}{b} = \cfrac{\sin |dw:1403057514568:dw|C}{c}}\]

OpenStudy (vishweshshrimali5):

That was actually: \[\large{\cfrac{\sin A}{a} = \cfrac{\sin B}{b} = \cfrac{\sin C}{c}}\]

OpenStudy (vishweshshrimali5):

A, B and C are angles at respective vertices and a,b,c are sides as represented in the figure.

OpenStudy (anonymous):

I got 20.80

OpenStudy (anonymous):

is that correct?

OpenStudy (vishweshshrimali5):

No try again.

OpenStudy (vishweshshrimali5):

See: \[\large{\cfrac{\sin C}{c} = \cfrac{\sin B}{b}}\]

OpenStudy (vishweshshrimali5):

Here, C = 30 deg , c = 11, B = 79 deg, b = ?

OpenStudy (anonymous):

@vishweshshrimali5 alright i got it thank you

OpenStudy (vishweshshrimali5):

np

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