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Please help factoring! x^2+8x+4y+8=0
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x^2+8x__= 4y+8
@Hero
Its a parabola that I need to write in standard form, find vertex, focus,directrix, and axis of symmetry
(x-h)^2=4p(y-k)
x^2+8x__= 4y+8 Add 16 both side and complete the square on the left hand
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|dw:1403080690584:dw|
so vertex is (4,-6)
(that should be a 4(y+6)
Your equation is x^2+8x+4y+8=0. right ?
yep
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Then you should have x^2 + 8x = -4y - 8
really? ok then vertex is (4,-2)
and p=-1
how do i find the focus,symmetry, and directrix?
Vertex should be 4,2
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oh thats right, theres a -4...
can you qualitatively draw this parabola ?
ummm im not sure...
i can plot the vertex but i dont know any points on the parabola curve
|dw:1403081395336:dw|
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