Question

What is the value of summation (2i^2+i-8)? I=1

Answer 1

\[{\Huge\sum_{i=1}^?}(2i^2+i-8)\]
What is the upper limit?

Answer 2

At any rate, these formulas should help:
\[\sum_{i=1}^n1=n\\
\sum_{i=1}^ni=\frac{n(n+1)}{2}\\
\sum_{i=1}^ni^2=\frac{n(2n+1)(n+1)}{6}\\
\sum_{i=1}^n(ai+b)=a\sum_{i=1}^ni+b\sum_{i=1}^n1\]