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If the distance covered by an object in time t is given by s(t) = 5t2 + t + 2, where s(t) is in meters and t is in seconds, what is the distance covered in the interval between 1 second and 4 seconds ? 72 meters 75 meters 78 meters 80 meters 81 meters
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see how much it covers in 1sec so you're asked to get the distance covered between 1 and 4 seconds so get the distance covered in 4secs then and subtract the distance covered in 1sec the difference will be the distance covered between 1 - 4 secs \(\bf s({\color{brown}{ 4}}) -s({\color{brown}{ 1}})\)
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