Question

x^2+2x+(y+1)^2-2=7

Answer 1

x^2+2x+(y+1)^2-2=7
x^2+2x+(y+1)^2=7+2
x^2+2x+(y+1)^2=14
how do i complete the square with this part x^2+2x+ ?

Answer 2

Okay so to complete the square you take the x number divide it in half and square it and that's the number that goes here:

Answer 3

So we have 2x. Half of 2 is 1 and 1^2 is 1 so: