Question

MArtha, lee, nancy, paul, jose and armando have been invited to a dinner party. they arrive randomly and each person arrives at different times. find the probability that martha arrvies first and armando last

Answer 1

There are 6! permutations of the order of arrival of all 6 guests. If Martha arrives first and Armando last, there are 4! permutations of the other 4 guests. Therefore the required probability is given by: 4!/6! = you can calculate.