the length of two sides of a triangle are, side 1 , 8x^2-5x-2, side 2 ,7x-x^2+3
the perimeter of the triangle is 4x^3-3x^2+2x-6
what is the length of the third side of the triangle?

Question

the length of two sides of a triangle are, side 1 , 8x^2-5x-2, side 2 ,7x-x^2+3
the perimeter of the triangle is 4x^3-3x^2+2x-6
what is the length of the third side of the triangle?

ganeshie8 · Answer

say the length of third side is $\large  a$

ganeshie8 · Answer

since perimeter is the sum of all the side lengths :

$\large   a +  (8x^2-5x-2 )  +  ( 7x-x^2+3 )   =   4x^3-3x^2+2x-6 $

ganeshie8 · Answer

isolate $\large  a$

bigbosssaint21 · Answer

how?

ganeshie8 · Answer

group like terms :
put all x^2 terms together, 
x terms together
constants together

ganeshie8 · Answer

$\large   a +  (8x^2 - x^2)  +  (-5+7x) + (-2+3)   =   4x^3-3x^2+2x-6 $

ganeshie8 · Answer

simplifying a bit gives you :

$\large   a +  (7x^2)  +  (2x) + (1)   =   4x^3-3x^2+2x-6 $

ganeshie8 · Answer

are you with me so far ? :)