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look at 40 degree angle. you have one side as 16 is is opposite side to 40 degree angle or adjacent side ??
Adjacent @hartnn
thats correct:) and 'x' is the hypotenuse so which ratio relates ADJACENT SIDE and HYPOTENUSE of a right triange ?
Tangent
tangent related opposite side and adjacent sides. not hypotenuse
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\(\huge \cos \theta =\dfrac{adjacent ~side }{hypotenuse} =??\)
here theta = 40 degrees
I'm getting 12.256 So is it B?
x = 16/ cos 40 = 16/0.766 = 20.887
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