Question

Multiply 2x^2(3x^2-4x)

Answer 1

\(2x^2(3x^2-4x)\)

distribute first:
\(2x^2(3x^2) - 2x^2(4x)\)

Then apply the exponent law: \(x^a * x^b = x^{a+b}\)

\(6x^4 - 8x^3\)