What are the foci of the graph Y^2/110-x^2/34=1?
(±8.7, 0)
(±12, 0)
(0, ±12)
(0, ±8.7)

Question

What are the foci of the graph Y^2/110-x^2/34=1?
	(±8.7, 0)
	(±12, 0)
	(0, ±12)
	(0, ±8.7)

loser66 · Answer

where are you stuck?

anonymous · Answer

i dont understand the question

loser66 · Answer

that's the standard form or a hyperbola with a = $\sqrt{110}$ and b=$\sqrt{34}$
the foci c =$\sqrt{a^2+b^2}$ calculate it.

anonymous · Answer

so just use that formula to answer the question?

loser66 · Answer

since a>b, then the major axis is vertical --> the vertex forms (0, a) --> the foci forms (0,c) also.

anonymous · Answer

so.....

anonymous · Answer

still dont understand

loser66 · Answer

I cooked the meal, I set the table. Your duty is eating. Do you want me feed you or even chew the food for you? Please, work.

anonymous · Answer

ok thanks for the help i got the answer