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What are the foci of the graph Y^2/110-x^2/34=1? (±8.7, 0) (±12, 0) (0, ±12) (0, ±8.7)
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where are you stuck?
i dont understand the question
that's the standard form or a hyperbola with a = \(\sqrt{110}\) and b=\(\sqrt{34}\) the foci c =\(\sqrt{a^2+b^2}\) calculate it.
so just use that formula to answer the question?
since a>b, then the major axis is vertical --> the vertex forms (0, a) --> the foci forms (0,c) also.
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so.....
still dont understand
I cooked the meal, I set the table. Your duty is eating. Do you want me feed you or even chew the food for you? Please, work.
ok thanks for the help i got the answer
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