Question

please help ?

Answer 1

cant open sorry

Answer 2

@Muzzack

Answer 3

BC=AC=?

Answer 4

7 @surjithayer

Answer 5

<AKB=100
<ADB=1/2*100=?

Answer 6

arc ADB=360-100=?

Answer 7

<ACB=180-100=?

Answer 8

centre is (4,-3)
radius=5

Answer 9

eq. of circle is \[\left( x-h \right)^2+\left( y-k \right)^2=r^2\]
(h,k)=(4,-3)
radius r=5

Answer 10

ADB=260?

Answer 11

ACB=80?

Answer 12

arc AB
\[\theta= \frac{ l }{ r },l=r*\theta ,\theta \in radians.\]
\[180 ~degrees=\pi~radians,100~degrees=\frac{ \pi }{ 180 }\times 100=\frac{ 5 }{ 9 }\pi\]
\[arc~AB=l=r \theta=5*\frac{ 5 }{ 9 }\pi\]

Answer 13

area ~of~sector~AB\[=\frac{ \pi r^2 }{ 360 }*100=?\]

Answer 14

area ~of~sector~AB =21.8?

Answer 15

1b. 7
2a. 100
2b.50
2c. 260
2d. 80
3a. 13.8
3b. 21.8

equation of a circle
\[(x-4)^{2} + (y+3)^{2} =25 \]

all of those are correct ? @surjithayer