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Mathematics
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OpenStudy (anonymous):
factor 2x 2 −6x−80
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OpenStudy (anonymous):
2x^2?
OpenStudy (anonymous):
2x^2 - 6x - 80
2(x^2 - 3x - 40)
Would be the first step right?
OpenStudy (anonymous):
Because were factoring ot the two.
OpenStudy (solomonzelman):
\(\normalsize\color{darkgreen}{ \rm 2x^2-6x-80 }\)
\(\normalsize\color{darkgreen}{ \rm 2(x^2-3x-40) }\)
\(\normalsize\color{red}{ \rm 2(x-8)(x+5) }\)
OpenStudy (anonymous):
@SolomonZelman Dont give them the answer... :/
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OpenStudy (solomonzelman):
you gave it away, they probably would not even know that that is the answer. xD
OpenStudy (anonymous):
I know.. haha but I wanted him to try. xD
OpenStudy (solomonzelman):
he would get it on yahoo or through a message. This is an easy question. So why not at leaast give it with e
OpenStudy (solomonzelman):
with explanation
OpenStudy (anonymous):
True.
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OpenStudy (solomonzelman):
This is a bad excuse to what I did though, you are right that I shouldn't have given it away.
OpenStudy (anonymous):
I just would hate to see your account get banned for the OS Code of conduct D:
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