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Find the vertex of f(x) = (x - 10)^2 - 8
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Please compare the given function with the following vertex form of the equation of a parabola: \[y=a(x-h)^2+k,\] where (h,k) is the vertex. In the given problem, what are the values of h and k?
h= -10 and k= -8
so is the vertex 10, -8? @mathmale
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