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Mathematics 21 Online
OpenStudy (anonymous):

2(x+y)^3-16

OpenStudy (dls):

so?

OpenStudy (anonymous):

Is it 2(x+y)^3-16 = 0 ?

OpenStudy (ikram002p):

^_^

OpenStudy (anonymous):

factor owt 2 first\[2(x+y)^3-16=2[(x+y)^3-8]\]for factoring \((x+y)^3-8\) note that \(8=2^3\) and use the identity\[a^3-b^3=(a-b)(a^2+ab+b^2)\]

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