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2(x+y)^3-16
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so?
Is it 2(x+y)^3-16 = 0 ?
^_^
factor owt 2 first\[2(x+y)^3-16=2[(x+y)^3-8]\]for factoring \((x+y)^3-8\) note that \(8=2^3\) and use the identity\[a^3-b^3=(a-b)(a^2+ab+b^2)\]
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