Bradley has 3 square pieces of cardboard with each side equal to x units. For each piece, he does something different to it according to each part below: Part A: Bradley pasted rectangular strips along two adjacent sides of the cardboard to increase its length and width by y units each. What will be the change in the area of the piece of cardboard? Show your work. Part B: Bradley cut off rectangular strips from two adjacent sides of the cardboard to decrease its length and width by y units each. What will be the change in the area of the piece of cardboard? Show your work.
Part C: Bradley cut off a strip from one side of the cardboard and pasted the strip on an adjacent side of the cardboard to increase its length by y units and decrease its width by y units. What will be the change in the area of the cardboard? Show your work.
1.So, the dimensions of the square are x and x Then,the area of the square piece=x*x=x^2 a)New length =x+y New breadth=x+y New area=(x+y)(x+y)=(x+y)^2 =x^2+2xy+y^2 { as (a+b)=a^2+b^2+2ab} Change in area=new area-old area =x^2+2xy+y^2-x^2 =2xy+y^2 b)New length =x-y new breadth=x-y new area=(x-y)(x-y)=(x-y)^2 {as (a-b)^2=a^2+b^2-2ab} =x^2-2xy+y^2 Change in area=new area-old area =x^2-2xy+y^2-x^2 =y^2-2xy c)New lenght=x+y new breadth=x-y new area=(x+y)(x-y) {as (a+b)(a-b)=a^2-b^2} =x^2-y^2 change in area=x^2-y^2-x^2 =-y^2 2.Length of rectangle = (4*2+2x-1) =8-1+2x =7+2x Width of the rectangle=3*3-x+4 =9+4-x =13-x a)area of the rectangle=l*b =(7+2x)(13-x) =7(13-x)+2x(13-x) =91-7x+26x-2x^2 =91+19x-2x^2 unit^2 b)Yes, as (7+2x)(13-x)=(13-x)(7+2x)=91+19x-2x^2 ( you can do the calculations if you want to check it.) c)The degree of polynomial is 2 as the highest power is 2 and thus it is a quadratic polynomial (based upon its degree).You can also classify it as trinomial based upon the number of terms it contains. Hope this helps and u understand all the identities i have used here
i do thanks!
wow thats a long problem
yes it is.
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