Question

5+√2x+1=10

Answer 1

\[\sqrt{2}x=10-1-5 \rightarrow \sqrt{2}x=4 \rightarrow x=\frac{ 4 }{ \sqrt{2} } \rightarrow x=\frac{ (2*2) }{ \sqrt{2} }\rightarrow x=\frac{ (\sqrt{2})^2(\sqrt{2})^2 }{ \sqrt{2} }\]\[\rightarrow x=(\sqrt{2})^3 \rightarrow x=2\sqrt{2}\]