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Find the sum of a finite arithmetic sequence from n = 1 to n = 13, using the expression 3n + 3. 42 300 52 312
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can you help me @imer
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thanks
what does it equals
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\[\sum_{n=1}^{13}3n+3=6+9+12+15+18+21+\] \[24+27+30+33+36+39+42=312\]
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