Question

c programming

Answer 1

how do i do this using while loops?

Answer 2

http://gyazo.com/ac6df48f177f71d51ecf9e04520918b3

Answer 3

you can iterate over array in a same way you'd do it with for():

int array_size = sizeof(array);
int i = 0;
while ( i < array_size) {
... insert all the code to check for various conditions in the task...
i++;
}

Answer 4

```
void classify(int array[], int n){
int i = 0;
while (i < n) {
int element = array[i++];
// rest of code
}
}
```

Answer 5

Do you need further help?

Answer 6

yes, i do..i dont to to know what im doing here ...

http://codepad.org/5R5moyZY

Answer 7

this is the solution with for loops... http://codepad.org/iyh1O3Hx

Answer 8

You need two variables, one to remember the first 0 and another to remember the second 0.

Answer 9

```
void classify(int array[], int n){
int i = 0, first = -1, second = -1;
while (i < n) {
int element = array[i];
if (element == 0) {
if (first == -1) {
first = i;
} else if (second == -1) {
second = i;
}
}
i++
}
// figure out the classification here
}
```

Answer 10

The first part just finds the position of the first two zeros

Answer 11

You could even improve the code a bit by doing:
```
void classify(int array[], int n){
int i = 0, first = -1, second = -1;
while (i < n) {
int element = array[i];
if (element == 0) {
if (first == -1) {
first = i;
} else if (second == -1) {
second = i;
break;
}
}
i++
}
// figure out the classification here
}
```
Since after you find the second zero, you don't need to continue the loop.