Question

4-x(2x-3)=16
quadratic equation.. help...

Answer 1

4-2x^2+3x=16
\[2x ^{2}-3x+12=0\]
now to find roots of a quadratic equation
\[ax ^{2}+bx+c=0\]
use this formula
\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 2

here, a=2, b=-3 and c=12

Answer 3

thanks... @neer2890

Answer 4

you're welcome...:)