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How do you find the value of x that makes the statement true. 3/7x+3-x+3=2
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Can you use parentheses to make your question clearer?
One solution was found : \(\color{blue}{\huge\cal\ x = 7~}\)
(3/7x+3)-(x+3)=2 better?
\(\frac{3}{7x+3}-(x+3)=2?\)
\[(\frac{ 3 }{ 7x }+3)-(x+3)=2\]
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how you wrote it does not help.... (3/7x+3)-(x+3)=2 is the same as \(\frac{3}{7x}+3-x-3\)
maybe draw it....
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