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Mathematics 21 Online
OpenStudy (anonymous):

y = Sqaure root of z find dy/dx when x is 25 given dy/dx is 2 this is a related rates problem

OpenStudy (anonymous):

square root of x

OpenStudy (zzr0ck3r):

this makes no sense.

OpenStudy (zzr0ck3r):

find dy/dx.....but then you say dy/dx = 2

OpenStudy (zzr0ck3r):

so the answer is 2

OpenStudy (anonymous):

oh its find dx/dt when x=25 given dy/dt =2

OpenStudy (zzr0ck3r):

write the problem exactly as asked

OpenStudy (anonymous):

assume that x and y are both differentiable functions of t and find the required values of dy/dy and dx/dt y=\[\sqrt{x}\] find dx/dt when x =25, given that dy/dt =2

OpenStudy (anonymous):

thats the whole thing

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

can someone help me please

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