Question

Find the point on the graph of f(x)= sqrt(x) where the tangent line has a slopw of 1/8.

The answer is (16, 4) but I am not sure how to get to it. Can someone help me please!? :)

Answer 1

st f'(x) = 1/8

Answer 2

set*

Answer 3

So do you do 1/8 = x ^1/2?

Answer 4

no f'(x) = (1/2) x^(-1/2)

Answer 5

ohhh sorry I didn't see the ' symbol

Answer 6

So what do you do after you have the derivative?

Answer 7

Oh, never mind I figured it out! Thank you!