Find the equation of the quadratic function with zeros 10 and 12 and vertex at (11, -2).

y = 2x^2 - 44x + 120

y = 2x^2 - 44x - 240

y = 2x^2 - 44x + 240

y = -2x^2 - 44x + 240

Question

Find the equation of the quadratic function with zeros 10 and 12 and vertex at (11, -2).

		
y = 2x^2 - 44x + 120
		
y = 2x^2 - 44x - 240
		
y = 2x^2 - 44x + 240
		
y = -2x^2 - 44x + 240

anonymous · Answer

I think it is c

anonymous · Answer

@jim_thompson5910 do you happen to know how to figure this out?

jim_thompson5910 · Answer

is that a guess or do you have something to back you up?

anonymous · Answer

It is more of a guess

jim_thompson5910 · Answer

it says "with zeros 10 and 12"

so which equation has y = 0 when x = 10?

anonymous · Answer

I'm not sure

anonymous · Answer

How do I find that out?

jim_thompson5910 · Answer

for each equation, plug in x = 10 and see which one results in y = 0

jim_thompson5910 · Answer

choice A

y = 2x^2 - 44x + 120

y = 2(10)^2 - 44(10) + 120

y = -120

so clearly x = 10 is NOT a root. So choice A is out

anonymous · Answer

Oh I see!