Question

a steel cable is 45m long and has a radius of 2.3cm. how much force is required to stretch it 0.15mm?
young's modules for steel is 210E9 N/m^2.

Answer 1

u still here

Answer 2

do u know anything about young's modulus?

Answer 3

Y = Stress/Strain
ever seen this formula? @cro825

Answer 4

Y=FL/(Al)
is ur formula needed

Answer 5

and that translates to f=YAL/Lo right?

Answer 6

F=YAl/L

Answer 7

thanks i will try that

Answer 8

u r most welcome

Answer 9

if u r pleaded on my solution then u can give me s medal

Answer 10

how i do that?

Answer 11

just click on right side of my name shamim

Answer 12

idk im getting 1.6E6 but not correct

Answer 13

2.3cm=?m

Answer 14

0.15mm=?m

Answer 15

.0023

Answer 16

no

Answer 17

.023

Answer 18

yes

Answer 19

now 0.15mm=?m

Answer 20

.00015

Answer 21

right

Answer 22

now use those data into ur formula

Answer 23

thought i was but i will again

Answer 24

so 210E9(.023)(.00015/45) ?

Answer 25

A=cross sectional area of given wire=πr^2

Answer 26

crap thought i could use the 2.3 cause it was not the dia i knew i was to find proper A and had the formua with me

Answer 27

sodo i use the cm or meter conv. in the area?

Answer 28

u hv to use m^2 for area

Answer 29

A=πr^2=3.1415*0.023^2m^2

Answer 30

ok i had that right then i over think at times so yes 210E9(1.66E-3)(.00015/45) = 1.2E3 for 2sf and was correct. thank you so much

Answer 31

got time for a similar?

Answer 32

welcome

Answer 33

anyway which grade u r

Answer 34

just for my curiosity

Answer 35

college. pretty slow arent i lol

Answer 36

no no

Answer 37

but im 40 and just stared back a yr ago

Answer 38

its ok

Answer 39

hm

Answer 40

r u frm usa

Answer 41

yes i am in georgia

Answer 42

so georgia is a state in usa. right?

Answer 43

yes

Answer 44

still around

Answer 45

tanks again the help me solve the next problem i had to b seeing were i went wrong on this one