Question

Please help--
find all solutions of the equation in the interval [0, 2pi) 2sin^2x-sin x-3=0
answer in radians

Answer 1

let sin x=t
2t^2-t-3=0

Answer 2

t=-1,3/2

Answer 3

t=3/2 is not possible

Answer 4

answers will be

Answer 5

3pi/2 is answer

Answer 6

thanks a lot for your help;)